The given question is a medium difficulty 3-mark question from the chapter Probability. The question has 3 parts one each to compute probability for a specific outcome when three different coins are tossed together. This probability question and appeared in Section C of the 2016 CBSE class 10 board paper.

Question 20: Three different coins are tossed together. Find the probability of getting

(i) exactly two heads

(ii) at least two heads

(iii) at least two tails

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3 different coins are tossed.

Total number of possibilities = 2 × 2 × 2 = 8

The 8 outcomes are HHH, HHT, HTH, THH, TTH, THT, HTT and TTT

Possible outcomes HHT, HTH, THH = 3 outcomes

∴ Probability = \\frac{\text{Number of outcomes of getting exactly 2 heads}}{\text{Total number of outcomes}})

= \\frac{3}{8})

**What does "at least 2 heads" mean?**

Minimum of 2 heads. i.e., 2 heads or 3 heads

Outcomes with 2 heads or 3 heads: HHT, HTH, THH, HHH = 4 outcomes

∴ Probability = \\frac{\text{Number of outcomes of getting at least 2 heads}}{\text{Total number of outcomes}})

= \\frac{4}{8}) = \\frac{1}{2})

**What does "at least 2 tails" mean?**

Minimum of 2 tails. i.e., 2 tails or 3 tails

Outcomes with 2 tails or 3 tails: TTH, THT, HTT, TTT = 4 outcomes

∴ Probability = \\frac{\text{Number of outcomes of getting at least 2 tails}}{\text{Total number of outcomes}})

= \\frac{4}{8}) = \\frac{1}{2})

Class 10 Maths

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