# 2018 Question Paper Solution | Question 6

###### CBSE Class 10 Maths | 1-Mark Questions | Section A | Similar Triangles

This is an easy 1-mark question from the chapter Triangles. Concept tested: Computing ratio of areas of two similar triangles when the ratio of the corresponding sides of the two triangles are given.

Question 6: Given ∆ ABC is similar to ∆ PQR. If $\frac{AB}{PQ} = \frac{1}{3}$, then find $\frac{ar ∆ ABC}{ar ∆ PQR}$

## NCERT Solution to Class 10 Maths

### Explanatory Answer | Q6 2018 Board Paper

Theorem: Ratio of the areas of two similar triangles is the square of the ratio of their corresponding sides.

$\frac{\text{Area of Δ ABC}}{\text{Area of Δ PQR}}$ = $\frac{\text{Square of corresponding side of ABC}}{\text{Square of corresponding side of PQR}}$ = $\frac{{AB}^2}{{PQ}^2}$
$\frac{\text{Area of Δ ABC}}{\text{Area of Δ PQR}}$ = $\frac{{AB}^2}{{PQ}^2}$ = $\frac{1^2}{3^2}$ = $\frac{1}{9}$

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