2018 Question Paper Solution | Question 6

CBSE Class 10 Maths | 1-Mark Questions | Section A | Similar Triangles

This is an easy 1-mark question from the chapter Triangles. Concept tested: Computing ratio of areas of two similar triangles when the ratio of the corresponding sides of the two triangles are given.

Question 6: Given ∆ ABC is similar to ∆ PQR. If $\frac{AB}{PQ} = \frac{1}{3}$, then find $\frac{ar ∆ ABC}{ar ∆ PQR}$

NCERT Solution to Class 10 Maths

Explanatory Answer | Q6 2018 Board Paper

Theorem: Ratio of the areas of two similar triangles is the square of the ratio of their corresponding sides.

$\frac{\text{Area of Δ ABC}}{\text{Area of Δ PQR}}$ = $\frac{\text{Square of corresponding side of ABC}}{\text{Square of corresponding side of PQR}}$ = $\frac{{AB}^2}{{PQ}^2}$
$\frac{\text{Area of Δ ABC}}{\text{Area of Δ PQR}}$ = $\frac{{AB}^2}{{PQ}^2}$ = $\frac{1^2}{3^2}$ = $\frac{1}{9}$

Try CBSE Online CoachingClass 10 Maths

Register in 2 easy steps and
Start learning in 5 minutes!

NCERT Solution to Exercise QuestionsCBSE Class 10 Maths

WhatsApp: WhatsApp Now
Email: learn@maxtute.com