2018 Question Paper Solution | Question 5

CBSE Class 10 Maths | 1-Mark Questions | Section A | Trigonometry

This 1-mark question is from the chapter Trigonometry. Concept tested: Trigonometric values of complementary angles.

Question 5: What is the value of (cos2 67° - sin2 23°)?


Target Centum in CBSE 10th Maths


Free Online CBSE Coaching
online.maxtute.com

Video Explanation


NCERT Solution to Class 10 Maths


With Videos


Explanatory Answer | Q5 2018 Board Paper

The given trigonometric expression is cos267° – sin223°
The expression is of the form (a2 - b2)
(a2 - b2) = (a + b)(a - b)
∴ cos267° – sin223° = (cos 67° + sin 23°) (cos 67° - sin 23°) ... eqn(1)

Trigonometric Ratio of Complementary Angles: sin (90 - θ) = cos θ
Let us express sin 23° = sin(90° - 67°)
sin (90° - 67°) = cos 67°

Substitute sin 23° as cos 67° in eqn(1)
(cos 67° + sin 23°) (cos 67° - sin 23°) = (cos 67° + cos 67°) (cos 67° - cos 67°)
(2 cos 67°) (0) = 0.



CBSE Online Coaching | Previous Year Question Paper Class 10 Maths 2018 Video Solution


WhatsApp: WhatsApp Now
Email: learn@maxtute.com