This CBSE class 10 Maths practice question is from the topic Trigonometry. It tests you the concept of trigonometric ratios of a right triangle and pythagoras theorem.

Question 1 : Consider right triangle ABC, right angled at B. If AC = 17 units and BC = 8 units determine all the trigonometric ratios of angle C.

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Length of the side BC = 8 units

Length of the side AC = 17 units

In Δ ABC, using Pythagoras theorem, AB = \\sqrt{AC^2− BC^2 })= \\sqrt{17^2− 8^2})

\\sqrt{289−64}) = \\sqrt{225}) ⇒ **AB = 15 units .**

sin C = \\frac{\text{opposite side}}{\text{hypotenuse}})=\\frac{\text{AB}}{\text{AC}})= \\frac{15}{17})

cos C = \\frac{\text{adjcent side}}{\text{hypotenuse}})=\\frac{\text{BC}}{\text{AC}})= \\frac{8}{17})

tan C =\\frac{\text{opposite side}}{\text{adjcent side}}) =\\frac{\text{AB}}{\text{BC}})= \\frac{15}{8})

cot C =\\frac{\text{1}}{\text{tan C}}) =\\frac{\text{adjcent side}}{\text{opposite side}}) = \\frac{\text{BC}}{\text{AB}}) = \\frac{8}{15})

sec C = \\frac{\text{1}}{\text{cos C}}) = \\frac{\text{hypotenuse}}{\text{adjcent side}}) = \\frac{\text{AC}}{\text{BC}})= \\frac{17}{8})

cosec C = \\frac{\text{1}}{\text{sin C}}) = \\frac{\text{hypotenuse}}{\text{opposite side}}) =\\frac{\text{AC}}{\text{AB}})= \\frac{17}{15})

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CBSE Class 10 Maths - 2020

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