This class 10 Maths extra question is from the topic Trigonometry. Concept Tested: Trigonometric values of basic angles.

Question 13: Find the value of x in each of the following.

(i) cosec 3x = \\frac{\text{cot 30° + cot 60°}}{\text{1 + cot 30° cot 60°}})

(ii) cos x = 2 sin 45° cos 45° – sin 30°

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cot 30° = √3 ; cot 60° = \\frac{1}{\sqrt{3}})

\\frac{\text{cot 30° + cot 60° }}{\text{1 + cot 30° cot 60° }}) = \\frac{\sqrt{3}+ \frac{1}{\sqrt{3}}}{1 + \sqrt{3} × \frac{1}{\sqrt{3}}}) = \\frac{\frac{(3+1)}{\sqrt3}}{2}) = \\frac{4}{\sqrt{3}}) × \\frac{\text{1}}{\text{2}})= \\frac{\text{2}}{\sqrt{3}})

So, cosec 3x = \\frac{2}{\sqrt{3}})

cosec 3x = cosec 60°

∴ 3x = 60° or x = 20°

sin 45° = cos 45°= \\frac{\text{1}}{\sqrt{2}}) ; sin 30° = \\frac{\text{1}}{\text{2}})

cos x = 2 sin 45° cos 45° – sin 30°= [ 2 × \\frac{\text{1}}{\sqrt{2}}) × \\frac{\text{1}}{\sqrt{2}}) ]- \\frac{1}{2})

cos x = 1 - \\frac{\text{1}}{\text{2}}) = \\frac{\text{1}}{\text{2}})

We know cos 60° = \\frac{\text{1}}{\text{2}})

∴ cos x = cos 60° or **x = 60° **

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CBSE Class 10 Maths - 2020

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