# Extra Questions For Class 10 Maths | Real Numbers Q7

#### Chapter 1 | HCF LCM Word Problem

This CBSE class 10 Maths Extra Question IS from the chapter Real Numbers. This extra question is a word problem that tests your understanding of which one to use - LCM or HCF?

Question - 7 : The Muscle Gym has bought 63 treadmills and 108 elliptical machines. The gym divides them into several identical sets of treadmills and elliptical machines for its branches located throughout the city, with no exercise equipment left over. What is the greatest number of branches the gym can have in the city?

## NCERT Solution to Class 10 Maths

#### With Videos

Given: Number of Treadmills = 63
Number of Elliptical machines = 108

#### Step 1 - What will represent the greatest number of branches?

Let the greatest number of branches in the city be 'n'.
Let the number of treadmills sent to each branch be 't' and the number of ellipticals sent to each branch be 'e'.
63 treadmills were distributed to 'n' branches with each branch getting 't' treadmills.
i.e., nt = 63
108 elliptical machines were distributed to 'n' branches with each branch getting 'e' elliptical machines.
i.e., ne = 108.

So, n is a factor of 63 and 108.
'n' is the greatest number of branches the gym can have in the city. So, 'n' is the HCF of 63 and 108.

#### Step 2 - Find HCF of 63 and 108

Step 1: Prime factorise 63 and 108.
63 = 32 × 7
108 = 22 × 33

Step 2: List down common primes.
3 is the only prime common to both the numbers.

Step 3: HCF is the product of lowest power of common primes in the 2 numbers.
Lowest power of 3 between 63 and 108 is 32.
Therefore, HCF = 9

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