# CBSE 2017 Board Paper

Class 10 Math Set 3 Q28. Quadratic Equation

#### Question Solve for x: $$frac{x - 1}{2x+1}$ + $\frac{2x+1}{x - 1}$ = 2; x ≠ $\frac{1}{2}$, 1 #### Video Explanation #### Explanatory Answer $\frac{x - 1}{2x+1}$ + $\frac{2x+1}{x - 1}$ = 2 Step 1: Take$x - 1)(2x + 1) as the common denominator.
$$frac {{\left$ {x-1} $right$}^{2}+{$left$ {2x+1} $right$}^{2}} {$2x+1)(x-1)}) = 2

Step 2: Cross multiply the denominator on the left side of the equation.
(x – 1 )2 + (2x + 1)2 = 2(2x + 1)(x – 1)

x2 – 2x + 1 + 4x2 + 4x + 1 = 4x2 - 4x + 2x – 2
5x2 + 2x + 2 = 4x2 – 2x – 2
x2 + 4x + 4 = 0

Step 3: Factorize the quadratic equation: x2 + 4x + 4 = 0
(x + 2)2 = 0
x = -2

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