Question 2: Find:
(i) \9^\frac{3}{2})
(ii) \32^\frac{2}{5})
(iii) \16^\frac{3}{4})
(iv) \125^\frac{-1}{3})
\9^\frac{3}{2}) = (32)\\frac{3}{2})
= 3(2 × \\frac{3}{2}))
= 33 = 27
\32^\frac{2}{5}) = (25)\\frac{2}{5})
= 2(5 × \\frac{2}{5}))
= 22 = 4
\16^\frac{3}{4}) = (24)\\frac{3}{4})
= 2(4 × \\frac{3}{4}))
= 23 = 8
\125^\frac{-1}{3}) = (53)\\frac{-1}{3})
= 5(3 × \\frac{-1}{3}))
= 5-1 = \\frac{1}{5})
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