Surface Areas & Volumes | Exercise 13.5 | Q7

Question 7: A godown measures 40 m × 25 m × 15 m. Find the maximum number of wooden crates each measuring 1.5 m × 1.25 m × 0.5 m that can be stored in the godown.

Explanatory Answer | Class 9 Maths Exercise 13.5 Q7

Step 1: Compute volume of the godown and volume of one wooden crate

Dimensions of the godown = 40 m × 25 m × 15 m
Volume of the godown = l × b × h
= 40 × 25 × 15 m³

Dimensions of the wooden crates = 1.5 m × 1.25 m × 0.5 m
Volume of one wooden crate = l × b × h
= 1.5 × 1.25 × 0.5 m³

Step 2: Compute the number of wooden crates that can be stored

Number of wooden crates that can be stored = \\frac{\text{Volume of godown}}{\text{Volume of one wooden crate}})
= \\frac{40 × 25 × 15}{1.5 × 1.25 × 0.5})
= 16,000 wooden crates

Note: Do not do calculations at the volume of godown and volume of one crate stage.
Do, the calculations at the last step. The numbers cancel in the numerator and denominator, making calculations easy.

Exercise 13.1 | Surface Area of Cubes & Cuboids

1. Class 9 Exercise 13.1 Question 3 | Height of hall ▶
2. Class 9 Exercise 13.1 Question 6 | TSA of Herbarium ▶
3. Class 9 Exercise 13.1 Question 7 | Shanti Sweets ▶

Exercise 13.2 | Surface Area of Cylinders

1. Class 9 Exercise 13.2 Question 3 | CSA TSA of Metal Pipe ▶
2. Class 9 Exercise 13.2 Question 4 | Roller & Playground ▶
3. Class 9 Exercise 13.2 Question 9 | Cylindrical Petrol Tank ▶
4. Class 9 Exercise 13.2 Question 10 | CSA of Decorative Lampshade ▶

Exercise 13.3 | Surface Area of Cones

1. Class 9 Exercise 13.3 Question 5 | Length of Tarpaulin 3 m wide ▶
2. Class 9 Exercise 13.3 Question 8 | Cost of painting conical barricades ▶

Exercise 13.4 | Surface Area of Spheres & Hemispheres

1. Class 9 Exercise 13.4 Question 8 | Outer CSA of hemispherical bowl ▶
2. Class 9 Exercise 13.4 Question 9 | Surface area of sphere & Cylinder ▶