Question 4: What is the area of the triangle formed by joining points (0, 5), (0, 11) and (8, 9)?

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Let the coordinates of the vertices of the triangle A, B, and C be (0, 5), (0, 11), and (8, 9) respectively.

Points A and B lie on the y – axis because their abscissa (x- coordinate) are zero.

Let AB be the base of the triangle.

Draw CD Parallel to x – axis. Coordinates of point D are (0, 9).

Because CD is perpendicular to AB, and is drawn from the vertex opposite to AB, CD is the altitude to base AB.

Length of AB = 6 Units.

Length of CD = 8 units.

Area of the triangle = \\frac{1}{2}) x base x altitude

= \\frac{1}{2}) x 6 x 8 = **24 sq. units**

Class 9 Maths

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