Question 4: If (x - 2a) is a factor of 2x4 - 4ax3 + 7x2 - 13ax - 18, find the value of a.
Let p(x) = 2x4 - 4ax3 + 7x2 - 13ax - 18
Because (x - 2a) is a factor of p(x), 2a is a zero of the polynomial.
∴ p(2a) = 0
p(2a) = 2(2a)4 - 4a(2a)3 + 7(2a)2 - 13a(2a) - 18 = 0
32a4 - 32a4 + 28a2 - 26a2 - 18 = 0
2a2 - 18 = 0
Or a2 = 9
Therefore, a = ±3
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