CBSE 10th Math Sample Paper 2019 | Q28A

This 2019 CBSE class 10 Maths 4 mark question is from Statistics. An important 4-mark question from statistics in CBSE class 10 sample question paper. Concept: Computing median when a frequency distribution table is given.

Question 28A: The median of the following data is 525. Find the values of x and y if the total frequency is 100.

Video Explanation

Explanatory Answer

It is given that n = 100
So, 76 + x + y = 100
i.e., x + y = 24 ------ 1

The median is 525, which lies in the class 500 – 600
Median = l + [\\frac{\frac{n}{2} − cf}{f}] \times h)
So, l = 500, f = 20, cf = 36 + x, h = 100

Using the formula: Median = l + [\\frac{\frac{n}{2} − cf}{f}] \times h)
525 = 500 + \\frac{50 − 36 − x}{20}) × 100

525 – 500 = (14 – x) × 5
25 = 70 – 5x
5x = 70 – 25 = 45
x = 9
From (1), x + y = 24 => 9 + y = 24
y = 15